18

Son zamanlarda çeşitli dillerde aşağıdaki gibi ( 1064 ) xkcd tarzı grafiklerin yeniden yaratılması ile ilgili oldukça fazla soru olmuştur .

Amacınız, mevcut xkcd çizgi romanlarını orijinaline mümkün olduğunca yakın bir şekilde yeniden oluşturmaktır. Çizgi roman en az bir basit grafik veya pasta grafik veya benzer bir öğeye sahip olmalıdır.

En yüksek oyu alan cevap kazanır , ilk geçerli cevaptan en geç 10 gün sonra .

Girişiniz, grafiksel bir dilde yukarıda açıklandığı gibi bir xkcd-comic'i görüntüleyen ve en azından çizim aracını (Mathematica, MatLab vb.) Kullanan bir kod içermelidir.

çizgi roman resim olarak saklanmamalı, prosedürel olarak oluşturulmalıdır
orijinal web sitesine veya bir aynaya veya sabit diskinizdeki içeriğe vb. herhangi bir bağlantı olmamalıdır.

Oylar sonuçların orijinal ile benzerliğini ve daha az ölçüde çözümün güzelliğini değerlendirmelidir. Burada hiçbir kod golf, ancak mümkün olduğunca kısa ve basit bir çözüm bekleniyor.

popularity-contest

— vsz
kaynak

3

Oyların çoğu uygun bir objektif kazanma koşulu değildir - ve Boolean oyları farklı boyutlarda birden fazla unsuru nasıl hesaba katar? Bu sorunun, kod uzunluğuna veya benzer bir şeye bölünmüş piksel başına ortalama hataya dayalı objektif bir kazanma koşulu olabileceğini düşünüyorum, ancak durduğu için insanları diğer yığınlarda ağır şekilde kaldırılmış cevapları kopyalayıp yapıştırmaya teşvik ediyor.

— Peter Taylor

1

@PeterTaylor: Bu yüzden mevcut bir xkcd komik olması gerektiğini belirtmiştim, bu yüzden kopyalama olmayacak. Çoğu upvotes yaygın olarak kullanılan bir ölçüttür (çok sevmediğim "ilk çözüm" ile birlikte), aksi takdirde burada nadiren kod golf olmayan (ve Golfscript tarafından kazanılmayan) herhangi bir sorun bulabilirsiniz

— vsz

8

İşte bir bıçak.

dipnot

[ Bu bir golf sorusu olmadığından sayı silindi. ]

xkcd1064

Daha elle çizilmiş görünmesi için bir "stil" bölümü eklendi.

xkcd1064, daha "elle çizilmiş"

Düzenleme: Helvetica, Courier'den daha iyi yanıt verir. Bu "stil" bölümünü değiştirdi ve geliştirdi. Ve yorumlar eklendi.

xkcd1064, eskisinden daha fazla "elle çizilmiş"

%!

%futz with a coordinate pair
/f { 2 { rand 100 mod 100 div 1.47 mul
        dup .4 mul sub add
        exch } repeat } def

/op 2 array def %original point
/cp 2 array def %current point
/setcp { 2 copy cp astore pop } def %set current point
/difcp { cp aload pop %x' y' x y   %diff between cp and point on stack
    3 2 roll exch sub %x' x y'-y
    3 1 roll sub %y'-y x'-x
    exch %dx dy
} def
/scale2 { /n exch def  %scale two values
    n mul exch n mul exch
} def
/add2 {
    3 2 roll add
    3 1 roll add exch
} def
%futz with a path
/fpath {
    2 {
    %flattenpath
    % replace lines with curves
    [ { setcp cp op copy pop /moveto cvx }
        {
            %cp aload pop 4 2 roll 2 copy
            2 copy difcp %x3 y3 x30 y30
            2 copy 1 4 div scale2 %x3 y3 x30 y30 (1/3)x30 (1/3)y30
            cp aload pop add2 %x3 y3 x30 y30 x1 y1
            4 2 roll 3 4 div scale2 %x3 y3 x1 y1 (2/3)x30 (2/3)y30
            cp aload pop add2 %x3 y3 x1 y1 x2 y3
            6 4 roll %x1 y1 x2 y2 x3 y3
            setcp
            /curveto cvx }
        { setcp /curveto cvx }
        { op cp copy pop /closepath cvx } pathforall ] cvx newpath exec
    % chop the curves
    flattenpath
    % futz all the points
    [ { f
        /moveto cvx }
        { f
            /lineto cvx }
        { %f
            f 6 2 roll
            f 6 2 roll
            f 6 2 roll
            2 copy
            /curveto cvx
            3 1 roll
            3{f}repeat /lineto cvx % extra triple-futz'd line after each curve
        }
        { /closepath cvx } pathforall ] cvx newpath exec
    } repeat
} def

%futz with strokes
/oldstroke /stroke load def
/stroke { fpath oldstroke } def

%futz with fills
/oldfill /fill load def
/fill { fpath oldfill } def

%make sure rectstroke doesn't bypass being futzed with
/rectstroke {
    4 2 roll moveto
    1 index 0 rlineto
    0 exch rlineto
    neg 0 rlineto
    closepath
    stroke
} def

%futz with strings
%by making sure show uses our futz'd fill
/show { gsave currentpoint newpath moveto dup
    false charpath 1{fpath}repeat fill grestore stringwidth rmoveto } def

%fatter lines
1 setlinejoin %round joins
currentlinewidth 1.9 mul setlinewidth
%chop curves very small so there's lots of points for futzing
currentflat 6 div setflat

/Helvetica 10 selectfont

<<
/in{72 mul}
>>begin
1 in 1 in translate

0 0 6 in 4 in rectstroke
1 in 3 in moveto (WALKING BACK TO MY) show
1 in 2.8 in moveto (FRONT DOOR AT NIGHT:) show

36 3.5 in moveto
0 -2.8 in rlineto
5 in 0 rlineto
3.45 in .55 in moveto
0 20 rlineto
4.05 in .55 in moveto
0 20 rlineto
2.7 in .40 in moveto
(YARD  STEPS DOOR  INSIDE ) show
0 .05 in rmoveto
.4 in 0 rlineto
currentpoint
stroke
moveto
-10 3 rlineto
0 -6 rlineto fill

2.6 in .45 in moveto
-2 in 0 rlineto
currentpoint
stroke
moveto
10 3 rlineto
0 -6 rlineto fill

(FEAR) .9 in 2.3 in moveto show
(THAT THERE'S) .9 in 2.1 in moveto show
(SOMETHING) .9 in 1.9 in moveto show
(BEHIND ME) .9 in 1.7 in moveto show
1.8 in 1.86 in moveto
2 -26 rlineto
stroke

(FORWARD) 2.2 in 2.1 in moveto show
(SPEED) 2.2 in 1.9 in moveto show
2.75 in 2 in moveto
3 -13 rlineto
stroke

(EMBARRASSMENT) 4.5 in 2.5 in moveto show
4.6 in 2.65 in moveto
-2 20
-5 22
-27 25 rcurveto
stroke

.6 setgray %gray
40 1.6 in moveto
2.7 in 0
2.9 in 20
3.2 in 1.5 in rcurveto
10 20
20 20
30 0 rcurveto
15 -1.7 in
30 -1.8 in
1.4 in -2 in rcurveto
stroke

0 0 1 setrgbcolor %blue
40 1.2 in moveto
.9 in 27
.8 in 20
1.4 in 21 rcurveto
1 in -20
1.2 in 6
1.3 in 1.6 in rcurveto
    10 20
    20 20
    30 0 rcurveto
15 -1.8 in
30 -1.9 in
1.8 in -2.1 in rcurveto
stroke

1 0 0 setrgbcolor %red
40 .9 in moveto
3.3 in 0
3.5 in 20
3.6 in 1.5 in rcurveto
10 72
20 80
30 80 rcurveto
.7 in -10
.3 in -35
1.1 in -40 rcurveto
stroke

%thank you for scrolling all the way down to here. :)

— luser droog
kaynak

"elle çizilmiş" stilizasyondan bazılarını ekleyebilir misiniz? :)

— Sam Ax

Evet. İlk başta bu yönü tamamen göz ardı ettim. Ve sonra bağlantıları takip ettiğimde tamamen bunalmıştım. Yağ hatları biggie olmamalıdır. Ve Casselman'dan bir yolu yeniden yorumlamak için bir yöntemim var. Bu matematiksel dönüşümleri anlayabilirsem, onları çoğaltabilmeliyim. Aslında düşündüğümden çok daha büyük bir görev.

— luser droog

Bu nitelikler olmasa bile, çok çok iyi bir iş.

— Sam Ax

Ve stil üzerinde süper harika bir iş!

— Sam Ax

7

HTML5

@font-face {
  font-family: 'Humor Sans';
  font-style: normal;
  font-weight: 400;
  src: local('Humor Sans'), local('Humor Sans-Regular'), 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<title>Front Door ( from xkcd.com 1064 )</title>
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<body><h1>Front Door <div class="h1d">( from xkcd.com 1064 )</div></h1>
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    style="font-size:14px;text-anchor:start">
    <tspan x="100.15588" y="48.485607" id="tspan7010">WALKING BACK TO MY</tspan>
    <tspan x="100.15588" y="65.285591" id="tspan7012">FRONT DOOR AT NIGHT:</tspan></text>
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    <tspan x="0.23551519" y="0.22564805">ThAT there's</tspan>
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    <tspan x="0.23551519" y="0.2723147">behing me</tspan></text>
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    <tspan x="0.52267832" y="0.46812996">door</tspan>
    <tspan x="0.58878779" y="0.46812996">inside</tspan></text>
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    <tspan x="0.63905853" y="0.20506927">emBARRASSMENT</tspan></text>
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Snippet'i genişlet

— F. Hauri
kaynak

4

piton

Matplotlib'de hafif cheat-y xkcd yöntemini kullanır:

import numpy as np
import matplotlib.pyplot as plt
from scipy.ndimage.filters import gaussian_filter1d

plt.xkcd()

x = np.linspace(0,10,1000)
unit = np.linspace(0,1,100)

speed = np.r_[np.ones(500)*3,3+5*unit**4.,np.ones(100)*8,1+7*unit[::-1]**2,np.ones(200)]
speed = gaussian_filter1d(speed,18)

fear = np.r_[np.linspace(0.5,2,450),2+6*unit**4,np.ones(100)*8,8*unit[::-1]**2,np.zeros(250)+0.1]
fear = gaussian_filter1d(fear,18)
fear_gauss_bump = 0.8*np.exp(-np.power(x-2.5,2.)/(2*np.power(1, 2.)))
fear += fear_gauss_bump

embarrassment = np.r_[np.zeros(600)+0.1, 9.5*unit**2, 9.5-np.linspace(0,1.5,300)]
embarrassment = gaussian_filter1d(embarrassment,60)

plt.figure(figsize=(12,6))
plt.plot(x,speed,c="gray")
plt.plot(x,fear,c="#1E9FDB")
plt.plot(x,embarrassment,c="r")

plt.plot([2.5,2.7],[3.9,2.3],c='k')
plt.plot([4.3,4.5],[3.6,3.1],c='k')
plt.plot(np.linspace(7.3,7.8,15),(0.25-(np.linspace(7.3,7.8,15)-7.3)**2)**0.5+7,c='k')

ax = plt.gca()
ax.spines['top'].set_visible(False)
ax.spines['right'].set_visible(False)
ax.get_xaxis().tick_bottom()
ax.get_yaxis().tick_left()
#plt.ylim([0,10])
ax.set_xticks([6,7])
ax.set_xticklabels(["STEPS","DOOR"])
ax.set_yticks([])

ax.text(2,4,"FEAR\nTHAT THERE'S\nSOMETHING\nBEHIND ME",horizontalalignment='center')
ax.text(3.9,3.4,"FORWARD\nSPEED",horizontalalignment='center')
ax.text(7.4,6.6,"EMBARRASSMENT")
ax.text(1,8,"WALKING BACK TO MY\nFRONT DOOR AT NIGHT:",bbox={'facecolor':'none', 'edgecolor':'black'})
ax.annotate("YARD", xy=(0.5,-0.3), xytext=(4.5,-0.4),annotation_clip=False,arrowprops={'facecolor':'black', 'shrink':0.01, 'width':0.5})
ax.annotate("INSIDE", xy=(10,-0.3), xytext=(7.5,-0.4),annotation_clip=False,arrowprops={'facecolor':'black', 'shrink':0.01, 'width':0.5})

plt.show()

— Kieran Avı
kaynak

En sevdiğiniz çizim aracıyla bir xkcd grafiğini yordamsal olarak yeniden oluşturun

dipnot

HTML5

piton