SELECT
  student.StudentID,
  student.`Name`,
  COUNT(attendance.AttendanceID) AS Total
FROM
  student
LEFT JOIN attendance ON student.StudentID = attendance.StudentID

Son satırı saymaya çalışıyorum ama bunun yerine tüm sonuçları sayar ve bir sonuç döndürür

Gibi bir şey alıyorum

K1052280 için Katılım Kimliği'nde iki giriş olduğundan birden fazla kayıt olduğundan bunları saymak ve numarayı döndürmek istiyorum. Gibi bir şey

GROUP BY grubunu kaçırıyorsunuz

GROUP BY İLE SORGUNUZ

SELECT
  student.StudentID,
  student.`Name`,
  COUNT(attendance.AttendanceID) AS Total
FROM
  student
LEFT JOIN attendance ON student.StudentID = attendance.StudentID
GROUP BY student.StudentID,student.`Name`;

ÖRNEK VERİ

DROP DATABASE IF EXISTS alishaikh; CREATE DATABASE alishaikh;
USE alishaikh
CREATE TABLE student
(
  StudentID CHAR(8) NOT NULL,
  Name VARCHAR(40),
  PRIMARY KEY (StudentID)
);
INSERT INTO student (StudentID,Name) VALUES
('k1052280','Ali Shaikh'),('k1052287','McKenzie Roth'),
('k1052288','Dacey Sullivan'),('k1052294','Zelda Cantu'),
('k1052295','Kimberly Melton'),('k1052296','Tatianna Cantrell'),
('k1052297','Morgan Thornton'),('k1052298','Allistair Barlow'),
('k1052299','Troy Fulton');
CREATE TABLE attendance
(
  AttendanceID INT NOT NULL AUTO_INCREMENT,
  StudentID CHAR(8) NOT NULL,
  PRIMARY KEY (AttendanceID),
  KEY (StudentID)
);
INSERT INTO attendance (StudentID) VALUES
('k1052280'),('k1052280'),('k1052287'),('k1052287'),
('k1052288'),('k1052295'),('k1052295'),('k1052295');

ÖRNEK VERİLER YÜKLENDİ

mysql> DROP DATABASE IF EXISTS alishaikh; CREATE DATABASE alishaikh;
Query OK, 2 rows affected (0.01 sec)
Query OK, 1 row affected (0.00 sec)
mysql> USE alishaikh
Database changed
mysql> CREATE TABLE student
    -> (
    ->   StudentID CHAR(8) NOT NULL,
    ->   Name VARCHAR(40),
    ->   PRIMARY KEY (StudentID)
    -> );
Query OK, 0 rows affected (0.03 sec)

mysql> INSERT INTO student (StudentID,Name) VALUES
    -> ('k1052280','Ali Shaikh'),('k1052287','McKenzie Roth'),
    -> ('k1052288','Dacey Sullivan'),('k1052294','Zelda Cantu'),
    -> ('k1052295','Kimberly Melton'),('k1052296','Tatianna Cantrell'),
    -> ('k1052297','Morgan Thornton'),('k1052298','Allistair Barlow'),
    -> ('k1052299','Troy Fulton');
Query OK, 9 rows affected (0.00 sec)
Records: 9  Duplicates: 0  Warnings: 0

mysql> CREATE TABLE attendance
    -> (
    ->   AttendanceID INT NOT NULL AUTO_INCREMENT,
    ->   StudentID CHAR(8) NOT NULL,
    ->   PRIMARY KEY (AttendanceID),
    ->   KEY (StudentID)
    -> );
Query OK, 0 rows affected (0.02 sec)

mysql> INSERT INTO attendance (StudentID) VALUES
    -> ('k1052280'),('k1052280'),('k1052287'),('k1052287'),
    -> ('k1052288'),('k1052295'),('k1052295'),('k1052295');
Query OK, 8 rows affected (0.00 sec)
Records: 8  Duplicates: 0  Warnings: 0

YÜRÜTÜLEN GRUP İLE SORGUNUZ

mysql> SELECT
    ->   student.StudentID,
    ->   student.`Name`,
    ->   COUNT(attendance.AttendanceID) AS Total
    -> FROM
    ->   student
    -> LEFT JOIN attendance ON student.StudentID = attendance.StudentID
    -> GROUP BY student.StudentID,student.`Name`;
+-----------+-------------------+-------+
| StudentID | Name              | Total |
+-----------+-------------------+-------+
| k1052280  | Ali Shaikh        |     2 |
| k1052287  | McKenzie Roth     |     2 |
| k1052288  | Dacey Sullivan    |     1 |
| k1052294  | Zelda Cantu       |     0 |
| k1052295  | Kimberly Melton   |     3 |
| k1052296  | Tatianna Cantrell |     0 |
| k1052297  | Morgan Thornton   |     0 |
| k1052298  | Allistair Barlow  |     0 |
| k1052299  | Troy Fulton       |     0 |
+-----------+-------------------+-------+
9 rows in set (0.00 sec)

mysql>

BİR ŞANS VER !!!