DATE SQL'den yalnızca Ay ve Yıl alınıyor

SQL Server'da yalnızca Ay.Yıl Tarih alanına erişmem gerekiyor.

Zaten verilen önerilerin yanı sıra, sorunuzdan çıkarabileceğim başka bir olasılık daha var:
- Sonucun hala bir tarih
olmasını istiyorsunuz - Ama Günleri, Saatleri vb. 'Atmak' istiyorsunuz
- Bir yıl / aydan ayrılmak sadece tarih alanı

SELECT
   DATEADD(MONTH, DATEDIFF(MONTH, 0, <dateField>), 0) AS [year_month_date_field]
FROM
   <your_table>

Bu, bir temel tarihten (0) itibaren tam ayların sayısını alır ve ardından bunları bu temel tarihe ekler. Böylece tarihin bulunduğu aya aşağı yuvarlanır.

NOT: SQL Server 2008'de, TIME hala 00: 00: 00.000 olarak eklenecektir. Bu, herhangi bir gün ve saat gösterimini "kaldırmak" ile tam olarak aynı değildir. Ayrıca GÜN birinci olarak ayarlandı. örneğin 2009-10-01 00: 00: 00.000

select month(dateField), year(dateField)

SELECT convert(varchar(7), getdate(), 126) 

Bu web sitesine göz atmak isteyebilirsiniz: http://anubhavg.wordpress.com/2009/06/11/how-to-format-datetime-date-in-sql-server-2005/

SELECT DATEPART(yy, DateVal)
SELECT DATEPART(MM, DateVal)
SELECT DATENAME(MM, DateVal)

datename(m,column)+' '+cast(datepart(yyyy,column) as varchar) as MonthYear

çıktı şöyle görünecek: "Aralık 2013"

Bunu yapmak için iki SQL işlevi vardır:

• DATEPART ()
• YEAR () ve MONTH () .

Ayrıntılar için bağlantılı belgelere bakın.

Bu da yardımcı olabilir.

SELECT YEAR(0), MONTH(0), DAY(0);

veya

SELECT YEAR(getdate()), MONTH(getdate()), DAY(getdate());

veya

SELECT YEAR(yourDateField), MONTH(yourDateField), DAY(yourDateField);

let's write it this way: YEAR(anySqlDate) and MONTH(anySqlDate). Try it with YEAR(GETDATE()) for example.

convert(varchar(7), <date_field>, 120)
because 120 results in 'yyyy-MM-dd' which is varchar(10)
using varchar(7) will display only year and month

example:
select convert(varchar(7), <date_field>, 120), COUNT(*)
from <some_table>
group by convert(varchar(7), <date_field>, 120)
order by 1

I am interpreting your question in two ways.

a) You only need Month & Year seperately in which case here is the answer

select 
        [YEAR] = YEAR(getdate())
        ,[YEAR] = DATEPART(YY,getdate())
        , [MONTH] = month(getdate())
        ,[MONTH] = DATEPART(mm,getdate())
        ,[MONTH NAME] = DATENAME(mm, getdate()) 

b)

You want to display from a given date say '2009-11-24 09:01:55.483' in MONTH.YEAR format. So the output should come as 11.2009 in this case.

If that is supposed to be the case then try this(among other alternatives)

select [Month.Year] = STUFF(CONVERT(varchar(10), GETDATE(),104),1,3,'')

Some of the databases such as MS ACCESS or RODBC may not support the SQL SERVER functions, but for any database that has the FORMAT function you can simply do this:

SELECT FORMAT(<your-date-field>,"YYYY-MM") AS year-date FROM <your-table>

RIGHT(CONVERT(VARCHAR(10), reg_dte, 105), 7) 

CONCAT (datepart (yy,DATE), FORMAT (DATE,'MM')) 

gives you eg 201601 if you want a six digit result

Try this

select to_char(DATEFIELD,'MON') from YOUR_TABLE

eg.

select to_char(sysdate, 'MON') from dual

Try this:

Portuguese

SELECT format(dateadd(month, 0, getdate()), 'MMMM', 'pt-pt') + ' ' + convert(varchar(10),year(getdate()),100)

Result: maio 2019

English

SELECT format(dateadd(month, 0, getdate()), 'MMMM', 'en-US') + ' ' + convert(varchar(10),year(getdate()),100)

Result: May 2019

If you want in another language, change 'pt-pt' or 'en-US' to any of these in link

I had a specific requirement to do something similar where it would show month-year which can be done by the following:

SELECT DATENAME(month, GETDATE()) + '-' + CAST(YEAR(GETDATE()) AS nvarchar) AS 'Month-Year'

In my particular case, I needed to have it down to the 3 letter month abreviation with a 2 digit year, looking something like this: SELECT LEFT(DATENAME(month, GETDATE()), 3) + '-' + CAST(RIGHT(YEAR(GETDATE()),2) AS nvarchar(2)) AS 'Month-Year'

Try SELECT CONCAT(month(datefield), '.', year(datefield)) FROM YOURTABLE;

My database doesn't support most of the functions above however I found that this works:

SELECT * FROM table WHERE SUBSTR(datetime_column, starting_position, number_of_strings)=required_year_and_month;

for example: SELECT SUBSTR(created, 1,7) FROM table;

returns the year and month in the format "yyyy-mm"

Get Month & Year From Date

DECLARE @lcMonth nvarchar(10)
DECLARE @lcYear nvarchar(10)

SET @lcYear=(SELECT  DATEPART(YEAR,@Date))
SET @lcMonth=(SELECT  DATEPART(MONTH,@Date))

SELECT REPLACE(RIGHT(CONVERT(VARCHAR(11), GETDATE(), 106), 8), ' ', '-')

Output: Mar-2019

Query :- Select datename(m,GETDATE())+'-'+cast(datepart(yyyy,GETDATE()) as varchar) as FieldName

Output :- January-2019

general datefield we can use

datename(m,<DateField>)+' '+cast(datepart(yyyy,<DateField>) as varchar) as FieldName

For result: "YYYY-MM"

SELECT cast(YEAR(<DateColumn>) as varchar) + '-' + cast(Month(<DateColumn>) as varchar)

select convert(varchar(11), transfer_date, 106) 

got me my desired result of date formatted as 07 Mar 2018

My column 'transfer_date' is a datetime type column and I am using SQL Server 2017 on azure

select CONCAT(MONTH(GETDATE()),'.',YEAR(GETDATE()))

Output: 5.2020

select CONCAT(DATENAME(MONTH , GETDATE()),'.',YEAR(GETDATE()))

Output: May.2020