Histogram (veri dağılımının grafiksel gösterimi) oluşturan en kısa programı yazın .

Kurallar:

• Programa girilen kelimelerin karakter uzunluğuna (noktalama işareti dahil) dayalı bir histogram oluşturulmalıdır. (Bir kelime 4 harf uzunluğundaysa, 4 sayısını temsil eden çubuk 1 artar)
• Çubukların temsil ettiği karakter uzunluğuyla ilişkili çubuk etiketleri görüntülenmelidir.
• Tüm karakterler kabul edilmelidir.
• Çubukların ölçeklendirilmesi gerekiyorsa, histogramda gösterilen bir yol olması gerekir.

Örnekler:

$ ./histogram This is a hole in one!
1 |#
2 |##
3 |
4 |###

$./histogram Extensive word length should not be very problematic.
1 |
2 |#
3 |#
4 |##
5 |
6 |##
7 |
8 |
9 |#
10|
11|
12|#

./histogram Very long strings of words should be just as easy to generate a histogram just as short strings of words are easy to generate a histogram for.
1 |##
2 |#######
3 |#
4 |#######
5 |###
6 |#
7 |##
8 |##
9 |##

K, 35

{(1+!|/g)#`$(#:'=g:#:'" "\:x)#'"#"}

.

k){(1+!|/g)#`$(#:'=g:#:'" "\:x)#'"#"}"Very long strings of words should be just as easy to generate a histogram just as short strings of words are easy to generate a histogram for."
1| ##
2| #######
3| #
4| #######
5| ###
6| #
7| ##
8| ##
9| ##

.

Daha uzun bir örnek

k){(1+!|/g)#`$(#:'=g:#:'" "\:x)#'"#"}"Please write a specification rather than giving a single example which, solely by virtue of being a single example, cannot express the range of acceptable output styles, and which doesnt guarantee to cover all corner cases. Its good to have a few test cases, but its even more important to have a good spec."
1 | #####
2 | ######
3 | #######
4 | ########
5 | ######
6 | ##############
7 | ###
8 | #
9 | ##
10| #
11|
12|
13| #

R, 55 47 karakter

hist(a<-sapply(scan(,""),nchar),br=.5+0:max(a))

Neyse ki R, histhistogramlar için bir çizim fonksiyonu ile birlikte gelir , burada breaksmolaların maksimum (giriş) +0,5'e kadar 0,5, 1,5, ... olduğu bir argümanla sağlanır . sapply(scan(,""),nchar)bir girdi alır (stdin olarak), boşluklardan sonra ayırır ve her öğenin karakter sayısını sayar.

Örnekler:

hist(a<-sapply(scan(,""),nchar),br=.5+0:max(a))
1: Extensive word length should not be very problematic.
9: 
Read 8 items

hist(a<-sapply(scan(,""),nchar),br=.5+0:max(a))
1: Very long strings of words should be just as easy to generate a histogram just as short strings of words are easy to generate a histogram for.
28: 
Read 27 items

Düzenle:

hist(a<-sapply(scan(,""),nchar),br=.5+0:max(a),ax=F);axis(1,at=1:max(a))

Python - 83 karakter

Herhangi bir yerden girdi alabileceğimiz anlaşılıyor, bu yüzden komut satırından ziyade yürütme sırasında girdi alıyor ve Ejrb'nin önerisini 8 kısaltmak için kullanıyor.

s=map(len,raw_input().split())
c=0;exec'c+=1;print"%3d|"%c+"#"*s.count(c);'*max(s)

Python - 91 karakter

Bu tırnak işaretleri ile düşecek.

import sys;s=map(len,sys.argv[1:])
for i in range(1,max(s)+1):print"%3d|"%i+'#'*s.count(i)

Giriş:

> python hist.py Please write a specification rather than giving a single example which, solely by virtue of being a single example, cannot express the range of acceptable output styles, and which doesnt guarantee to cover all corner cases. Its good to have a few test cases, but its even more important to have a good spec.

Çıktı:

  1|#####
  2|######
  3|#####
  4|##########
  5|######
  6|#############
  7|####
  8|#
  9|##
 10|#
 11|
 12|
 13|#

Haskell - 126 karakter

p[d]=[' ',d];p n=n
h l=[1..maximum l]>>= \i->p(show i)++'|':(l>>=($"#").drop.abs.(i-))++"\n"
main=interact$h.map length.words

Bu stdin, komutu komut satırından değil , girişten alır :

& head -500 /usr/share/dict/words | runhaskell 15791-Histogram.hs 
 1|##
 2|##
 3|######
 4|###############
 5|################################################
 6|###############################################################
 7|###################################################################
 8|###########################################################################
 9|#############################################################
10|##########################################################
11|#########################################################
12|#########################
13|#######
14|###
15|#####
16|###
17|#
18|
19|#
20|#

Python 3,3 (93)

a=[len(i) for i in input().split()]
for i in range(1,max(a)+1):
 print(i,'|',"#"*a.count(i))

Çıktı:
(ilk satır giriş dizesidir)

Very long strings of words should be just as easy to generate a histogram just as short strings of words are easy to generate a histogram for.
1 | ##
2 | #######
3 | #
4 | #######
5 | ###
6 | #
7 | ##
8 | ##
9 | ##

Lego Stormtroopr'un Python çözümü (benimkinden daha kısa) olarak sayıları haklı çıkarmıyor, ama bir golf yarışmasında ilk girişim bu yüzden sanırım burada bırakabilirim :)

Perl, 56

$d[y///c].='#'for@ARGV;printf"%2d|$d[$_]
",$_ for+1..$#d

@ Manatwork'ün yeniden yazma ve gerçek satırsonu önerisi eklendi, çok teşekkürler! @ Chinese_perl_goth adlı kullanıcının güncellemeleri eklendi.

Kullanım: hist.pl olarak kaydedin ve çalıştırın perl hist.pl This is a test

Örnek çıktı:

$perl ~/hist.pl This is a test of the histogram function and how it will count the number of words of specific lengths. This sentence contains a long word 'complexity'.
 1|##
 2|#####
 3|####
 4|######
 5|##
 6|#
 7|
 8|#####
 9|#
10|
11|#

J, 48 47 46 45 43 karakter

(;#&'#')/"1|:((],[:+/=/)1+[:i.>./)$;._1' ',

Kullanımı:

   (;#&'#')/"1|:((],[:+/=/)1+[:i.>./)$;._1' ','Very long strings of words should be just as easy to generate a histogram just as short strings of words are easy to generate a histogram for.'
┌─┬───────┐
│1│##     │
├─┼───────┤
│2│#######│  
├─┼───────┤
│3│#      │
├─┼───────┤
│4│#######│
├─┼───────┤
│5│###    │
├─┼───────┤
│6│#      │
├─┼───────┤
│7│##     │
├─┼───────┤
│8│##     │
├─┼───────┤
│9│##     │
└─┴───────┘

Yakut, 98 85

a=$*.group_by &:size
1.upto(a.max[0]){|i|b=a.assoc i
puts"%-2i|#{b&&?#*b[1].size}"%i}

Çok golf değil. Daha sonra golf olacak.

c:\a\ruby>hist This is a test for the histogram thingy. yaaaaaaaaaaaay
1 |#
2 |#
3 |##
4 |##
5 |
6 |
7 |#
8 |
9 |#
10|
11|
12|
13|
14|#

Powershell, 97 93

$a=@{};$args-split ' '|%{$a[$_.length]++};1..($a.Keys|sort)[-1]|%{"{0,-2} |"-f $_+"#"*$a[$_]}

Misal:

PS Z:\> .\hist.ps1 This is an example of this program running
1  |
2  |###
3  |
4  |##
5  |
6  |
7  |###

APL (42)

⎕ML←3⋄K,⊃⍴∘'▓'¨+⌿M∘.=K←⍳⌈/M←↑∘⍴¨I⊂⍨' '≠I←⍞

Değerin 0 olduğu satırları atlayabilirsem daha kısa olabilirdi.

Açıklama:

• ⎕ML←3: taşıma düzeyini 3 olarak ayarlayın (bu, ⊂(bölüm) daha kullanışlı hale getirir ).
• I⊂⍨' '≠I←⍞: okuma girişi, boşluklara bölünmüş
• M←↑∘⍴¨: her öğenin ilk boyutunun boyutunu (kelime uzunlukları) alın ve M
• K←⍳⌈/M: 1'den en yüksek değere kadar olan rakamları alın M,K
• +⌿K∘.=M: içindeki her değer için M, kaç kez içerildiğine bakın K.
• ⊃⍴∘'▓'¨: bu değerdeki her değer için o kadar çok ▓s'nin listesini alın ve bunu bir matris olarak biçimlendirin.
• K,: Ketiketleri vererek her değeri matristeki her satıra yerleştirir.

Çıktı:

      ⎕ML←3⋄K,⊃⍴∘'▓'¨+⌿M∘.=K←⍳⌈/M←↑∘⍴¨I⊂⍨' '≠I←⍞
This is a hole in one!
1 ▓  
2 ▓▓ 
3    
4 ▓▓▓
      ⎕ML←3⋄K,⊃⍴∘'▓'¨+⌿M∘.=K←⍳⌈/M←↑∘⍴¨I⊂⍨' '≠I←⍞
Very long strings of words should be just as easy to generate a histogram just as short strings of words are easy to generate a histogram for.
1 ▓▓     
2 ▓▓▓▓▓▓▓
3 ▓      
4 ▓▓▓▓▓▓▓
5 ▓▓▓    
6 ▓      
7 ▓▓     
8 ▓▓     
9 ▓▓     

Mathematica 97

Histogram["" <> # & /@ StringCases[StringSplit[InputString[]], WordCharacter] /. 
a_String :> StringLength@a]

Bağımsızlık Bildirgesi'nin metnini tek bir dize olarak girdiğimde (elbette kes ve yapıştır ile), üretilen çıktı:

Dördüncü, 201

Bu eğlenceliydi ama Ruby sunumum daha rekabetçi. ;-)

variable w 99 cells allot w 99 cells erase : h begin
1 w next-arg ?dup while swap drop dup w @ > if dup w
! then cells + +! repeat w @ 1+ 1 ?do i . 124 emit i
cells w + @ 0 ?do 35 emit loop cr loop ; h

Örnek çalışma:

$ gforth histo.fth Forth words make for tough golfing!
1 |
2 |
3 |#
4 |#
5 |###
6 |
7 |
8 |#

Maksimum kelime uzunluğu 99'dur.

Yakut, 79

(1..(w=$*.group_by &:size).max[0]).map{|i|puts"%2i|#{?#*w.fetch(i,[]).size}"%i}

Örnek çalışma:

$ ruby hist.rb Histograms, histograms, every where, nor any drop to drink.
 1|
 2|#
 3|##
 4|#
 5|#
 6|##
 7|
 8|
 9|
10|
11|##

Gülmek için lütfen Dördüncü gönderime bakın.

Yakut 1.8.7, 74

Diğer yakut çözeltilerinden biraz farklı bir yaklaşım:

i=0;$*.map{|v|v.size}.sort.map{|v|$><<(i+1..v).map{|n|"
%2i:"%i=n}+['#']}

çıktı:

ruby hist.rb `head -400 /usr/share/dict/words`

 1:#
 2:###
 3:######
 4:#############################
 5:#####################################################
 6:############################################################
 7:########################################################################
 8:######################################################
 9:############################################################
10:########################
11:###########################
12:######
13:#####

JavaScript ( 159133 )

Kesinlikle rekabetçi değil, ama şimdiye kadar tek JavaScript çözümü. @Manatwork kullanmanın ipucu için teşekkürler String.replace.

prompt(o=[]).replace(/\S+/g,function(p){o[l=p.length]=(o[l]||'')+'#'});for(i=1;i<o.length;)console.log(i+(i>9?"|":" |")+(o[i++]||""))

Giriş

Kod Golf bulmaca meraklıları ve kod golfçüler programlama için bir soru ve cevap sitesidir. Soru-cevap sitelerinin Stack Exchange ağının bir parçası olarak sizin tarafınızdan oluşturulmuş ve işletilmektedir. Sizin yardımınızla birlikte, programlama bulmacaları ve çözümlerinin bir kütüphanesini oluşturmak için birlikte çalışıyoruz.

Çıktı

1 |##
2 |#######
3 |#########
4 |########
5 |######
6 |###
7 |####
8 |####
9 |
10|#
11|###

Saf bash 120

d="$@"
d=${d//[ -z]/#}
for a;do((b[${#a}]++));done
e="${!b[@]}"
for((i=1;i<=${e##* };i++));do
echo $i\|${d:0:b[i]}
done

Örneklem:

./histogram.sh Very long strings of words should be just as easy to generate a histogram just as short strings of words are easy to generate a histogram for.
1|##
2|#######
3|#
4|#######
5|###
6|#
7|##
8|##
9|##

Bir çatal kullanarak 8 karakter kazanın tr: 112

for a;do((b[${#a}]++));done
e="${!b[@]}"
for((i=1;i<=${e##* };i++));do
printf "%d|%${b[i]}s\n" $i
done|tr \  \#

Aynı sonucu verin:

bash -c 'for a;do((b[${#a}]++));done;e="${!b[@]}";for((i=1;i<=${e##* };i++));
do printf "%d|%${b[i]}s\n" $i;done|tr \  \#' -- $( sed 's/<[^>]*>//g;
s/<[^>]*$//;s/^[^<]*>//' < /usr/share/scribus/loremipsum/english.xml )

render (sunucumda :)

1|############################################################
2|#################################################################################################################################################################################################################
3|####################################################################################################################################################################################################################################################
4|####################################################################################################################################################################################################
5|####################################################################################################################################################################
6|#######################################################################################
7|##########################################################################################
8|###################################################
9|###############################
10|####################
11|#########
12|############
13|#####
14|####
15|##
16|
17|
18|
19|
20|
21|
22|
23|
24|
25|
26|
27|
28|
29|
30|
31|
32|
33|
34|#

PHP, 162

<?php error_reporting(0);$b=0;while($argv[$b])$c[strlen($argv[++$b])]++;for($t=1;$t<=max(array_keys($c));$t++)echo $t.'|'.($c[$t]?str_repeat('#',$c[$t]):'')."\n";

Kullanımı:

php histogram.php Very long strings of words should be just as easy to generate a histogram just as short strings of words are easy to generate a histogram for.
1|##
2|#######
3|#
4|#######
5|###
6|#
7|##
8|##
9|##

8 , 162 bayt

kod

a:new ( args s:len nip tuck a:@ ( 0 ) execnull rot swap n:1+ a:! ) 0 argc n:1- loop 
a:len n:1- ( dup . "|" . a:@ ( 0 ) execnull "#" swap s:* . cr ) 1 rot loop bye

kullanım

$ 8th histogram.8th Nel mezzo del cammin di nostra vita mi ritrovai per una selva oscura

Çıktı

1|
2|##
3|####
4|#
5|##
6|###
7|
8|#

Açık kod ( SED Yığın Etki Diyagramıdır)

a:new               \ create an empty array 
( 
    args s:len      \ length of each argument
                    \ SED: array argument lengthOfArgument
    nip             \ SED: array lengthOfArgument
    tuck            \ SED: lengthOfArgument array lengthOfArgument
    a:@             \ get item array at "lengthOfArgument" position
    ( 0 ) execnull  \ if null put 0 on TOS
                    \ SED: lengthOfArgument array itemOfArray
    rot             \ SED: array itemOfArray lengthOfArgument    
    swap            \ SED: array lengthOfArgument itemOfArray
    n:1+            \ increment counter for the matching length
    a:!             \ store updated counter into array 
) 0 argc n:1- loop  \ loop through each argument
\ print histogram
a:len n:1- ( dup . "|" . a:@ ( 0 ) execnull "#" swap s:* . cr ) 1 rot loop 
bye                 \ exit program